# Is supernetting allowed in Cisco Packet Tracer

## Documentation date: IP addressing. Date: information. Version: 1.0. Minutes from page 1

IP addressing Author: Schmid Tobias Type: Information Version: 1.0 Protocol from 04/05/2016 page 1

Contents CONTENTS 1 First steps ... 3 2 Exercises for IP addressing ... 5 3 Subnetting theory ... 7 3.1 About these instructions ... 7 3.2 Subnetting A task with the solution .... 7 3.3 Subnetting calculation .. . 8 4 Subnetting calculation ... 12 5 Solutions ... 16 Protocol from 04/05/2016 page 2

2 exercises for IP addressing 1. Calculate the maximum number of network devices in the respective subnet if they have the following network mask or prefix: a) 255.255.255.0 g) 255.255.255.192 m) / 23 b) 255.255.0.0 h) 255.255. 224.0 n) / 20 c) 255.255.255.128 i) 255.252.0.0 o) / 12 d) 255.255.255.240 j) 255.255.255.252 p) / 30 e) 255.255.254.0 k) / 16 q) / 25 f) 255.255. 128.0 l) / 29 r) / 8 2. Calculate the minimum network mask (in decimal and prefix notation) for the networks with the specified number of network devices: a) 12 e) 4 i) 2 b) 36 f) 4'080 j ) 2'047 c) 170 g) 14 k) 224 d) 110 h) 32'430 l) 1 3. Calculate the associated network address, the broadcast address and the maximum number of network devices in the same network for the following network address specifications: a) 192.168 .1.30 255.255.255.0 h) 192.168.13.130/26 b) 160.85.160.255 255.255.224.0 i) 62.2.244.109/30 c) 176.255.13.22 255.255.255.224 j) 10.0.33.33/27 d) 179.248.222.18 255.255.255.252 k) 181.15.33.233/20 e) 10.10.0.255 255.248.0 .0 l) 10.55.0.4/12 f) 209.1.3.254 255.255.254.0 m) 33.33.32.0/19 g) 223.19.127.255 255.255.128.0 n) 62.3.256.13/23 Protocol from 04/05/2016 page 5

3.3 Subnetting calculation protocol from 04/05/2016 page 8

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4 Subnetting calculation Step 1: So that a network can be divided into smaller subnets, the network portion should be expanded by a certain number of bits in the network mask. In the first step, this number of bits is calculated. The number of bits required depends on the number of subnets required. Number of bits: 1 2 3 4 5 6 7 8 Number of subnets: 2 4 8 16 32 64 128 256 With 1 bit, 2 ^ 1 = 2 subnets can be set up. But 4 subnets are necessary. With 2 bits we can build 2 ^ 2 = 4 subnets. The power supply unit must therefore be expanded by 2 bits. Intermediate step: Convert the host part into a binary number. Here, only those octets are converted into the binary number that are not equal to 255 in the network mask. (In this example: 255.255.255.0) IP address: 192.168.168.0 Net mask: 255.255.255.0 => 192.168.168.00000000 255.255.255.00000000 Step 2: Expand the network part by 2 bits. IP address: 192.168.168.00000000 Netmask: 255.255.255.00000000 => 192.168.168.00000000 255.255.255.11000000 The network portion was expanded by 2 bits in the netmask. (From left to right) Minutes from April 5th, 2016, page 12